An arithmetic series consists of consecutive integers that are multiples are of 4. what is the sum of the first nine terms of this sequence if the first term is 0 a. 160 b. 162 c. 180 d. 198

 The answer is 144.

Step-by-step explanation: Let 'a' be the first term and 'd' be the common difference of the given arithmetic progression (A.P.).

According to the given information, A.P. is {0, 4, 8, 12, 16, . . .}, i.e., a=0 and d=4.

The sum of first n terms is given by

So, the sum of first 9 terms is

Thus, the required sum is 144.