You measure the boiling point of water to be 98.5°c, 99.3 °c, and 99.8°c. the true boiling point is 100°c. what is your percent error, based on your average measurements? type your answer as a percentage, rounded to the nearest tenths place.

The percent error based on the average measurements is 0.8%.

Step-by-step explanation:

The standard equation for percent error is [(original - actual)/original} x 100.  The original amount is 100 degrees celcius.  Your average measurement can be found by adding the three temperatures together and dividing by the number of temperatures collected:  98.5 + 99.3 + 99.8 = 297.63/3 = 99.2.  When we place our numbers into the equation and solve, we get:  (100 - 99.2)/100 = 0.008 x 100 (to get our percentage) = 0.8%.

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: