Given: ad = cf bc = de prove: ab = ef statement reason 1. ad = cf given 2. ad = ab + bc + cd cf = cd + de + ef segment addition 3. ab + bc + cd = cd + de + ef transitive property of equality 4. ab + bc = de + ef 5. bc = de given 6. ab = ef subtraction property of equality what is the reason for the fourth statement in this proof? a. definition of collinear points b. segment addition c. subtraction property of equality d. substitution property of equality

option C is correct.

It is Subtraction Property of Equality.

Step-by-step explanation:

Since, we are given the following statements for a proof:

1.     AD =CF  given

2.    AD = AB + BC + CD CF = CD + DE + EF segment addition

3.   AB + BC + CD = CD + DE + EFTransitive Property of Equality

4.  AB + BC = DE + EF

5.   BC = DEgiven

6. AB = EFSubtraction Property of Equality

As in third step we are given:

AB + BC + CD = CD + DE + EF

and going to the fourth step we are left with the term:

AB + BC = DE + EF

This means we are using subtraction property of equality.

" Since, CD term is same on both the sides of the equality so we subtract it from both the sides so as to get step fourth and proceed further for the proof ".

Hence, option C is correct.

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

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