What equation results from completing the square and then factoring x^+4x=7

The resulting equation is (x + 2)^2 = 11

Step-by-step explanation:

It is given that,  x^2 + 4x=7  (1)

The quadratic equation is of the form ax^2 + bx + c = 0

in completing square method we have to add( b/2)² in both the sides

In eq (1) b = 4, then b/2 = 4/2 = 2

Therefore we have to add 2^2 = 4 in both sides of the eq (1)

eq (1) becomes   x^2 + 4x + 4=7  + 4

x^2 + 4x + 4 = 11

(x + 2)^2 = 11

Therefore the resulting equation is

(x + 2)^2 = 11

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i