How many grams of co are needed with an excess of fe2o3 to produce 27.9 g fe? show work.

Step-by-step explanation:

Moles Fe = 209.7 g / 55.847 = 3.75

the ratio between CO and Fe is 3 : 2

Moles CO needed = 3.75 x 3 / 2 = 5.63

Mass CO = 5.63 mol x 28.01 g/mol =157.7 g

I think? Correct me if i'm wrong!

hope this !

step-by-step explanation:

d = distance between moon and sun, which in this problem is the hypotenuse of a right triangle.  

the distance y is the side opposite to angle x in the right triangle.   use the definition of the sine function from basic trigonometry.

sin(x) = y/d ⇒

d = y/sin(x)

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb