Brayden, howard, and vincent are on the football team. during a game, brayden gains 1 less than 5 times the average number of yards gained per play during the game. howard runs for 1 more than 5 times the average number of yards gained per play during the game. vincent runs for 5 more than 4 times the average number of yards gained per play during the game. in this activity, you will write equations to describe this situation and determine whether the equations have one solution, no solution, or infinitely many solutions. question 1 part a : write an expression for each player’s yards gained in terms of y, the average number of yards gained per play during the game.

The average number of yards gained per play is y. Brayden gains 1 less than 5 times the average number of yards gained per play during the game. So, the expression 5y − 1 will represent the number of yards gained by Brayden.

Howard runs for 1 more than 5 times the average number of yards gained per play during the game. So, the expression 5y + 1 will represent the number of yards gained by Howard.

Vincent runs for 5 more than 4 times the average number of yards gained per play during the game. So, the expression 4y + 5 represents the number of yards gained by Vincent.

Step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.