Evaluate the following logarithms. log12 144 = log15 1 = log3 ( 1 81 ) = log 0.00001 =

Answer(s): (2,0,-4,-5)

log12 144 =  2

log15 1 = 0

log3 (  1/ 81  )  = -4

log 0.00001 =  -5

step-by-step explanation: a reaction is first order. if the initial reactant concentration is 0.0200 m, and 25.0 days later the concentration is 6.25 x 10-4 m, then its half-life is:

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)