What are the solutions to 6x ^ 2 - 5x - 4 equals 0

x = - , x =

Step-by-step explanation:

given 6x² - 5x - 4 = 0

Factorise by considering the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x term, that is

product = 6 × - 4 = - 24 and sum = - 5

The factors are + 3 and - 8

Use these factors to split the middle term

6x² + 3x - 8x - 4 = 0 ( factor the first/second and third/fourth terms )

3x(2x + 1) - 4(2x + 1) = 0 ( take out common factor (2x + 1) )

(2x + 1)(3x - 4) = 0

equate each factor to zero and solve for x

2x + 1 = 0 ⇒ 2x = - 1 ⇒ x = -

3x - 4 = 0 ⇒ 3x = 4 ⇒ x =

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.