Two sides of a triangle measure 2x – 4 and 7x – 2 units, respectively. which of these is a possible length for the third side of the triangle? a 3xb 6xc 5x+2d 9x-6

Step-by-step explanation:

Given two sides of a triangle 2x – 4 and 7x – 2 units.

Difference of two sides of a triangle is less than third side.

Let us find the difference of 7x – 2 and 2x – 4, we get

7x-2 - (2x-4) = 7x -2 -2x +4

= 5x + 2.

Third side should be less then 5x+2, so 5x+2 can't be third side.

Sum of two sides is greater than third side.

Adding given sides of triangle, we get

7x-2 +2x-4 = 9x - 6.

Third side should be greater than 9x-6. So, 9x-6 can't be third side.

Now, if we add 3x and 2x-4, we get

3x+2x-4 = 5x-4, which is less than 9x - 6.

So, 3x can't be third side.

Therefore, correct option is :

7

step-by-step explanation:

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer