At 7: 30 am a bus left townp for town q at a speed of 60 klms per hour. 15 minutes later, a car left left town q and headed for town p. the car reached town p at 10: 45 a. m. the bus reached town q at noon. a) what the distance between town p and town q? b) what was the speed of the car?

a) 270 km

b) 90 km/h

Step-by-step explanation:

If a car left left town Q 15 minutes later than bus left town P, then the car left town Q at 7:45 p.m. Since the car reached town P at 10:45 a.m., then the car was hours on the road.

If a bus left town P at 7:30 and reached town Q at 12:00, then the bus was hours on the road. Since the speed of the bus is 60 km/h, then the distance between towns P and Q is

Now the speed of the car is

step-by-step explanation:

where is the questions

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3