Expand (x-y)^5 using pascal’s triangle

Hello from MrBillDoesMath!

x^5 - 5 x^4 y + 10 x^3 y^2 - 10 x^2 y^3 + 5 x y^4 - y^5

Discussion:

Pascal's triangle looks like this (up to 6 rows)

    1  

   1 1  

  1 2 1  

 1 3 3 1  

1 4 6 4 1  

1  5 10 10 5 1

The last row contains the constant multipliers in the equation. The terms in the expansion alternate in sign.

Thank you,

MrB

i can

step-by-step explanation:

really really sorry if i'm

-12 -5(x + 4) = 3x

-12 - 5x - 20 = 3x

-12 - 20 - 5x = 3x

-32 - 5x = 3x

    + 5x   + 5x

-32 = 8x

8         8

- 4= x