Ok theres two questions i need the equation and answer. 1. write an equation of the line in slope intercept form that has a slope -2/3 and has a y-intercept of -42. write and equation of a line in slope intercept form that passes through the points (3 , -2) and (1 , 4)

1)   y = -2/3x - 4

2)  y = -3x + 7

Step-by-step explanation:

1)  Plug in the slope (m) and y intercept (b) into the equation

     y = mx + b

     y = -2/3x - 4

2)  Find  the slope (m)  m = y₂ - y₁/ x₂ - x₁

                                      m =  4 - (-2)/1 - 3

                                      m =  6/-2

                                     m = -3

   Then find the y intercept (b) by plugging x, y and m into y = mx + b (you can choose either point given

4 = -3 ( 1) + b

4 = -3 + b

Add 3 to both sides

7 = b

So now you know  m = -3 and b = 7  

Plug into y = mx + b

                y = -3x + 7

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

30 people weigh 160 pounds or more