If s(x)= 2-x^2 and t(x)=3×, which value is equivalent to ( s(t(×)) (-7)

Step-by-step explanation:

Given that s(x)= 2-x^2 and t(x)=3×

To find which value is equivalent to ( s(t(×)) (-7)

This is composition of functions where t is performed first and then s

x=-7

t(-7)=

NOw s(t(-7))=s()

=

simplify to get

1.99999

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry