What is the equation of the graph below? a graph shows a parabola that opens down and crosses the x axis near one and a half and four and a half. a) y = − (x + 2)2 + 2 b) y = − (x − 3)2 + 2 c) y = (x − 2)2 + 2 d) y = (x + 3)2 + 2

B)

Step-by-step explanation:

We are given,

The graph of the parabola opens downwards.

This means that the leading co-efficient of the function will be negative.

So, options C and D are not possible.

Moreover, it is given that the graph cuts x-axis near i.e. = 1.5 and i.e. = 4.5.

i.e. At y=0, the value of x is near and .

A. So, in , we put y =0.

i.e.

i.e.

i.e. x = 0.68 and x = 3.41

We see that this does not crosses the x-axis at the given points.

So, option A is wrong.

B. Also, in , we put y =0.

i.e.

i.e.

i.e. x = 1.68 and x = 4.41.

Thus, this equation cuts the x-axis near the given points i.e. 1.5 and 4.5.

Hence, the equation of the given graph is .