Hey! last day for me to do algebra before exams so this is an would definitely be appreciated and do not answer unless you know the answers! you.

Part 1 -

1. f(x) = 5(x-2)^2 + 4

axis of symmetry: x = 2

vertex: (2, 4)

2. f(x) = 12(x + 6)^2 - 5

axis of symmetry: x = -6

vertex:  (-6, -5)

3. f(x) = 2x^2 + 8x - 7

axis of symmetry: x = -2

vertex: (-2, -15)

I have to go somewhere right now, but I will get back to you as soon as I can (probably within a couple of hours) to finish answering the rest of your questions.

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step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.