What is the equation of the line, in point slope form, that passes through the given point and has the given slope? point: (11,3) slope: 4/11

The point-slope form:

We have the point (11, 3) and the slope m = 4/11. Substitute:

Step-by-step explanation:

To find the equation, we have to use the point-slope formula:

Where is the slope and is the points through the line passes.

So, from the problem we have:

Replacing these elements, we have:

Therefore, the equations is

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐