What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−2/3x+5 ? enter your answer in the box.

Step-by-step explanation:

We are to find the equation a line that passes through the point (8, 1) and which is perpendicular to a line whose equation is.

We know that the slope of line which is perpendicular to another line is the negative reciprocal of the slope of the other line so it will be .

Then, we will find the y-intercept of the line using the standard equation of a line:

Therefore, the equation of the line will be .

the equation is y'=

Step-by-step explanation:

A line is given whose equation is given as ------(1)

and we have to find the equation of another line which is perpendicular to this.

Let the equation of the line be y'=mx'+c------(2)

This line passes through a point (8,1) so we put the values of x & y in the equation.

⇒ 1 = m×8+c

⇒ 8m+c = 1------(3)

We know that if two lines are perpendicular to each other then multiplication of their slopes is equal to (-1).

Therefore m×=(-1)

⇒

⇒m=

Now we put the value of m in equation (3) to get the value of c

8×+c = 1

12+c=1

c = (-11)

Therefore the equation will be y'=

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step-by-step explanation:

because i said it is