The perimeter of a basketball court is 266 ft, and its length is 35 ft more than its width. find the dimensions of the court.

w = 49 ft and l = 84ft

Step-by-step explanation:

P = 266

The formula for perimeter = 2(l+w)

We know the length is 35 more than the width

l = w+35

Substituting in for Perimeter

266 =2(l+w)

Now replacing l with w+35

266 =2(w+35+w)

Combine like terms

266 = 2(2w+35)

Divide each side by 2

266/2 = 2/2 (2w+35)

133 = 2w+35

Subtract 35 from each side

133-35 = 2w+35-35

98 = 2w

Divide by 2

98/2 = 2w/2

49 =w

We still need to find l

l = w +35

l = 49+35

l = 84

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: