Which point to is the solution set of the given system of inequalities?

the second one is the answer

Step-by-step explanation:I did this last year

The point that lie in the solution set of the given system of inequalities is:

                          (0,0)

We are given a system of inequality as:

          3x+y ≥ -3(1)

and    x+2y ≤ 4(2)

From the given points we will check which satisfies both the inequality and hence the one which satisfies will be a solution.

a)

                (5,0)

on putting in inequality (1) we get:

  15≥  -3

and from inequality (2) we get:

             5≤4

which is incorrect.

Hence, option: a is not a solution.

b)

                 (-2,0)

on putting in inequality (1) we get:

        -6 ≥ -3

which is incorrect( since -6<-3)

Hence, option: b is incorrect.

c)

                          (0,3)

on putting in inequality (1) we get:

                    3 ≥ -3

which is true

on putting in inequality (2) we get:

         6 ≤ 4

which is incorrect.

Hence, option: c is false.

d)

             (0,0)

on putting in inequality (1) we get:

   0 ≥ -3

which is  a true expression.

on putting in inequality (2) we get:

              0 ≤ 4

which is a true expression.

Hence, the point (0,0) will lie in the solution set.

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

answer is 12345678900987654321234567890987654321

step-by-step explanation: