Three vertices of a quadrilateral are (-1 -1), (1,2) and (5, -1). what are the coordinates of two vertices that will form two different parallelograms?

Choose any two vertices from {(-5, 2), (7, 2), (3, -4)}

Step-by-step explanation:

Any pair of the given vertices can be one diagonal of the parallelogram. Then the fourth vertex is found by adding the two points of the chosen pair and subtracting the remaining point. Then coordinates of the 4th vertex could be ...

... (-1, -1) +(1, 2) -(5, -1) = (-1+1-5, -1+2+1) = (-5, 2)

or

... (-1, -1) +(5, -1) -(1, 2) = (-1+5-1, -1-1-2) = (3, -4)

or

... (1, 2) +(5, -1) -(-1, -1) = (1+5+1, 2-1+1) = (7, 2)

_____

The method we have described for finding the remaining point comes from the fact that the two diagonals of a parallelogram intersect at their midpoints. If M is the midpoint of diagonals AC and of BD of parallelogram ABCD, then ...

... M = (A+C)/2 = (B+D)/2

... A+C = B+D . . . . multiply by 2

... A+C-B = D . . . . . . the fourth point is the sum of opposite points less the third one.

describing distributions is one of the key skills you’ll need to earn a high score on the ap statistics exam. if you need proof of this, just flip through some past exam questions, which can be found at the collegeboard website. you’ll notice that the first free response question is almost always a question requiring you to look at a graph and describe it.

step-by-step explanation: just trying to get points sorry : (