Which equation has the root x = -3 in addition to the same two roots as the equation x^2-2x-24=0

Hello from MrBillDoesMath!

x^3 + x^2 - 30x - 72

Discussion:

The polynomial

( x - (-3))  (x^2 -2x - 24 )

has the requested roots

(x + 3) ( x^2 -2x-24) =

x^3 + x^2 - 30x - 72

Thank you,

MrB

6 and -4

Step-by-step explanation:

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°