Atrapezoid has an area of 60 square feet. if the trapezoid has a base measuring 4 feet and a height of 12 feet, what is the length of the other base? a. 4 ft b. 6 ft c. 10. ft d. 12 ft

Let a = given base

Let b = the other base

Let h = height

A = (1/2)(a + b)h

60 = (1/2)(4 + b)(12)

We now solve for b.

60 = 6(4 + b)

60 = 24 + 6b

60 - 24 = 6b

36 = 6b

36/6 = b

6 = b

The other base measures 6 feet.

B

Step-by-step explanation:

the area of a trapezoid (A) is calculated using the formula

A = h(a + b)

where h is the height and a, b the parallel sides

here h = 12, a = 4 and A = 60, hence

× 12(4 + b) = 60

6(4 + b) = 60 ( divide both sides by 6 )

4 + b = 10 ( subtract 4 from both sides )

b = 6

Hence the other base = 6 ft → B

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

then