What is the equation of the following line written in slope-intercept form? y = x - 13/3 y = x - 13/3 y = -x - 13/3

y = -2/3 x - 13/3

Step-by-step explanation:

We have one point at (-5,-1)  and there is another point at (1,-5)

The slope is

m= (y2-y1)/(x2-x1)

   = (-5--1)/(1--5)

  = (-5+1)/(1+5)

  = -4/6

=-2/3

The point slope form of the equation is

y-y1 = m(x-x1)

y--1 = -2/3(x--5)

y+1 =-2/3( x+5)

Distribute

y+1 = -2/3 x -10/3

Subtract 1 from each side

y +1-1 = -2/3 x -10/3 -1

Get a common denominator

y = -2/3 x -10/3 -3/3

y = -2/3 x - 13/3

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

step-by-step explanation:

where is the question is there is a formula or is there not one