Find the sample variance and standard deviation. 6, 52, 16, 51, 35, 23, 28, 28, 32, 26

Sample variance is 199.79 and standard deviation 14.13

Step-by-step explanation:

Number of values: n=10

Mean: M=(6+52+16+51+35+23+28+28+32+26)/10

M=(297)/10→M=29.7

Sample Variance: v

v=[(6-29.7)^2+(52-29.7)^2+(16-29.7)^2+(51-29.7)^2+(35-29.7)^2+(23-29.7)^2+(28-29.7)^2+(28-29.7)^2+(32-29.7)^2+(26-29.7)^2]/(10-1)

v=[(-23.7)^2+(22.3)^2+(-13.7)^2+(21.3)^2+(5.3)^2+(-6.7)^2+(-1.7)^2+(-1.7)^2+(2.3)^2+(-3.7)^2]/(9)

v=[561.69+497.29+187.69+453.69+28.09+44.89+2.89+2.89+5.29+13.69]/(9)

v=[1,798.1]/(9)

v=199.7888888

v=199.79

Standard deviation: s

s=sqrt(v)

s=sqrt(199.7888888)

s=14.13466974

s=14.13

3, nah jk it's 2

step-by-step explanation:

it is 3 cause i'm sanic

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%