The equation a=1/2(b1+b2)h can be used to determine the area, a, of a trapezoid with height, h, and base lengths, b1 and b2. which are equivalent equations? check all that apply.

b₁ = (2a – b₂h)/h; b₁ = (2a)/h – b₂; h = (2a)/(b₁ + b₂)

Step-by-step explanation:

A. Solve for b₁

          a = ½(b₁ + b₂)h        Multiply each side by 2

        2a = (b₁ + b₂)h           Remove parentheses

        2a = b₁h + b₂h           Subtract b₂h from each side

2a - b₂h = b₁h                    Divide each side by h

         b₁ = (2a – b₂h)/h     Remove parentheses

         b₁ = (2a)/h – b₂

B. Solve for h

2a = (b₁ + b₂)h     Divide each side by (b₁ + b₂)

 h = (2a)/(b₁ + b₂)

c. (3,2,6) is the answer.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2