If (6^2)^x =1 what is the value of x

x = 0

Step-by-step explanation:

Rewrite (6^2)^x =1 as 6^(2x) = 1.

Next, take the logarithm (common or natural) of both sides, obtaining

2x log 6 = log 1

2x log 6 = 0

Then x = 0.

Note that (6^2)^0 = 1, since any positive number raised to the prower 0 is 1.

step-by-step explanation:

idk the answer i want to say 10 but then it would be equal so try 9 but then yeah so yeah we love edgen

answer:

c) the x-coordinate of the center of the circle increases by 3