98 points and ! the equation below represents function a and the graph represents function b: function a f(x) = - 2x + 1 function b which equation best compares the slopes of the two functions? slope of function b = 2 x slope of function a. slope of function a = slope of function b slope of function a = 2 x slope of function b slope of function b = - slope of function a

Slope of Function B = - Slope of Function A

Step-by-step explanation:

Function A

f(x) = - 2x + 1

This is in the form y = mx+b where m is the slope

The slope is -2

Function B

We have 2 points so we can calculate the slope

(0,-3) and (2,1)

m = (y2-y1)/(x2-x1)

   = (1--3)/(2-0)

   = (1+3)/(2-0)

    =4/2

2

Slope of A = -2       Slope B =2

The are opposites

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.