Ramon was studying pond life in doyle park. in two hours, he counted four more frogs than turtles. the number of crayfish he counted was three more than twice the number of turtles. in total, he counted 54 turtles and crayfish. how many frogs were there?

frogs = 13

Step-by-step explanation:

Lets denote

    Turtle  as   t

     Frog   as   f

     Crayfish  as  c

Two hours has nothing to do with the answer, it is added just to confuse the student.

He counted four more frogs than turtles

   t = 4 + f  ( 1 )

Number of crayfish was three more than twice the number of turtles

  c = 3 + 2 ( t ) ( 2 )

Total, he counted 54 turtles and crayfish

  t + c = 54 ( 3 )  

How many forgs

  f = ?

From eq ( 3 )

  c = 54 - t ( 4 )

put c in eq ( 2 )

  54 - t = 3 + 2 ( t )

  54 - 3 = 2 ( t ) + t

  51 = 3 ( t )

  t  =  17 ( 5 )

put t in eq ( 1 )

 17 = 4 + f

 f = 17 - 4

 f = 13 ( 6 )

For finding c put t = 17 in eq ( 4 )

 c = 54 -  17

 c = 37

To check if the answer is right, put values of t and c in eq 3

 17 + 37 = 54

 54 = 54 L.H.S = R.H.S

i believe the answer is d.

hope it you! : d

don't know what that says sorry i can't you

step-by-step explanation:

idk what it says