Given: △abc is an isosceles triangle, ac - base △bdc is an equilateral triangle perimeter of △abc = 42, ac = 12 find: perimeter of △bdc

Perimeter of △BDC=Sum of all the sides=BD+DC+CB=15+15+15=45

Step-by-step explanation:

Given ΔABC is an isosceles triangle, thus, AB=BC=x and AC=12,

perimeter of  △ABC is=42

⇒x+x+12=42

⇒2x=30

⇒x=15

Thus, AB=BC=15

Now, △BDC is an equilateral triangle therefore BD=DC=BC=x

Since, x=15, therefore BD=DC=BC=15

Now, Perimeter of △BDC=Sum of all the sides=BD+DC+CB=15+15+15=45

The perimeter is 45 cm

Step-by-step explanation:

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complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation:

the answer is b