(5r-4)(r^2-6r+4) what is the product

Distribute sum groups

5r(r^2 - 6r + 4) -4(r^2 - 6r + 4)

Distribute

5r^3 - 30r^2 + 20r - 4(r^2 - 6r + 4)

Distribute

5r^3 - 30r^2 + 20r - (4r^2 - 24r + 16)

Simplify brackets

5r^3 - 30r^2 + 20r - 4r^2 + 24r - 16

Collect like terms

5r^3 (-30r^2 - 4r^2) + (20 + 24r) - 16

Simplify

5r^3 - 34r^2 + 44r - 16

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

4th option is correct xy=-10

if this was to u plzz mark me the brainliest