Abag contains, red, blue and yellow balls the probability of picking a red ball is 1/3 the probability of picking a blue ball is 1/5 a.) work out the probability of picking a yellow ball b.) there are 10 red balls how many balls are there in total c.) grace adds 10 balls to the bag so that: p(red) = 1/4 and p(blue) = 2/5 how many of each color does she add space out your answer and label 'a' 'b' and 'c'

a)

b) There are 30 balls

c) Number of blue balls added = 10, number of red balls added = 0 and number of yellow balls added = 0

Step-by-step explanation:

a) Sub of the probabilities is always 1.

Therefore,

p(red) + p(blue) + p(yellow) = 1

b) p(red ball) =

But, it is given that n(E) = 10

Therefore,

n(S) = 30

Hence, there are 30 balls in total

c) From b), there are 10 red balls.

Now, p(blue ball) =

Since, n(S) = 30,

n(E) = 6

There are 6 blue balls and

the number of yellow balls = 30 - (10 + 6) = 14

After adding 10 balls, n(S) = 40

p(blue ball) =

= 16

But, number of blue balls before addition = 6.

Hence, all the added balls are blue.

after simplifying it i got: -36.25 as my answer. hope that !

srry idk

step-by-step explanation: