Dont guess i have to get this question ! 20 points show your work ! ! write an equation in point-slope form for the line though the given point with given slope. (8,3); m = 6 a. y - 3 = 6 (x+8) b. y - 3 = 6 (x-8) c. y + 3 = 6 (x-8) d. y + 3 = 6x + 8

oops i just did :)

Point-slope form is y - y_1 = m (x - x_1) where x_1 and y_1 are the given coordinates and m is the slope. When you plug the given values into the equation you get y - 3 = 6 (x - 8) .

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.