The table shows the break down of the number of juniors and seniors taking foreign languages and which foreign language they are taking. what is the relative frequency for juniors taking spanish? a) 0.239 b) 0.436 c) 0.547 d) 0.761 this is chartforeign languages juniors seniorsfrench 32 20german 25 30latin 18 15spanish 58 45will give brainliest

All I have to say is the answer is A. :I

Step-by-step explanation:

A) 0.239

Step-by-step explanation:

This depends on precise meaning of "relative frequency." Three of the choices appear in the spreadsheet:

A) 0.239 is number of Juniors taking Spanish, divided by total number of students.

B) 0.436 is number Juniors taking Spanish, divided by total number of Juniors.

C) 0.547 is total number of Juniors divided by total number of students.

C and D are obviously wrong.

Absent a precise definition, some judgment is required to decide between A and B. Does "Relative" mean "relative to the class" or "relative to all Juniors and Seniors"? I think the latter, which is choice A.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

y -5 = (-1/4)(x + 8)

step-by-step explanation: