Asap 30 pts + brainliest to right/best answer

y = 2(x+2)^2 -5

Step-by-step explanation:

y= 2x^2 +8x+3

Factor out a 2 from the first 2 terms

 y = 2(x^2 +4x) +3

 Complete the square

(4/2)^2 = 4  But we are multiplying by 2 on the outside  so we add 8.  If we add 8 we need to subtract 8 to balance the equation

y = 2 (x^2 + 4x+4) -8 +3

Combine like terms

y = 2(x+2)^2 -5

C

Step-by-step explanation:

y = (2x^2 + 8x) + 3                            Take out the coefficient in front of x^2

y = 2(x^2 + 4x) + 3                             Take 1/2 the x term coefficent and square

y = 2(x^2 + 4x + (4/2)^2 ) + 3 - 2(4/2)^2   Subtract the same amount outside the brackets.

y = 2(x + 4/2)^2 + 3 - 8          Present what is inside the brackets as a perfect square.

y = 2(x + 2)^2 - 5                     Combine

C

step-by-step explanation: