Aparallelogram is shown below: part a: what is the area of the parallelogram? show your work. part b: how can you decompose this parallelogram into two triangles? if this parallelogram was decomposed into two triangles, what would be the area of each triangle? 30 points for anyone with an answer!

A:  6 ft²

B:  3 ft² is the area of each of the two congruent triangles

Part A. As with a rectangle, the area of a parallelogram is the product of base length and height.

  Area = (8 ft)·(3/4 ft) = 6 ft²

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Part B. If you cut the area into two halves, each half will have half the area of the original. (That should not be a surprise.)

  triangle area = (6 ft²)/2 = 3 ft²

If the triangles are created by a diagonal across the original figure, each will have a base length and height that is the same as that of the original figure. The area of a triangle is half the product of base and height, so each triangle will have area ...

  triangle area = (1/2)bh = (1/2)(8 ft)(3/4 ft) = 3 ft²

A:  6 ft^2

3 ft^2 is the area of each of the two congruent triangles

Step-by-step explanation:

Part A. As with a rectangle, the area of a parallelogram is the product of base length and height.

 Area = (8 ft)·(3/4 ft) = 6 ft^2

Part B. If you cut the area into two halves, each half will have half the area of the original. (That should not be a surprise.)

 triangle area = (6 ft^2)/2 = 3 ft^2

If the triangles are created by a diagonal across the original figure, each will have a base length and height that is the same as that of the original figure. The area of a triangle is half the product of base and height, so each triangle will have area ...

 triangle area = (1/2)bh = (1/2)(8 ft^2)(3/4 ft)

3ft^2

72 is the answer to this problem

it has the same slope and a different y-intercept

hope this : )