15 pts + brainliest to right/best answer

Rewrite it in the form; a^2 + 2ab + b^2, where a = 3x and b = 8

(3x)^2 + 2(3x)(8) + 8^2

Use the Square of Sum: (a + b)^2 = a^2 + 2ab + b^2

(3x + 8)^2

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8