Select from the drop-down menus to correctly complete the proof. to prove that 3√2 is irrational, assume the product is rational and set it equal to a/b , where b is not equal to 0: 3√2=a/b . isolating the radical gives √2=a/3b . the right side of the equation is choose (rational or irrational) . because the left side of the equation is choose (rational or irrational) , this is a contradiction. therefore, the assumption is wrong, and the number 3√2 is choose (rational or irrational).