The function h is defined by h(x)=60÷x−r, where r is a constant. find r, if the graph of h passes through the point (−6,−20).

r = 10

Step-by-step explanation:

You want to find r such that ...

  -20 = 60/-6 -r

  r = 60/-6 +20 . . . . . add 20+r

  r = -10 +20 = 10

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If you mean h(x) = 60/(x -r), then the answer is different.

  -20 = 60/(-6-r)

  -6-r = 60/-20 . . . . . multiply by (-6-r)/(-20)

  -r = -3 +6 = 3 . . . . . add 6, simplify

  r = -3 . . . . . . . . . . . . multiply by -1

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form