What is the sum of the first nine terms of this sequence if the first term is 0?

D. 160

Step-by-step explanation:

The sum of the sequence 1, 2, 3, 4, ... , n is n(n + 1)/2.

Here, you have the sum of 4(1, 2, 3, 4, ... , n), so the sum is 4[n(n + 1)/2]

In this case, the first term is 0, so the last term is the 8th term of the sequence above, so n = 8

4[n(n + 1)/2)] =

= 4[8(9)/2]

= 4[72/2]

= 4(36)

= 144

The closest answer is D. 160

452,489 to the nearest thousand is 452,000

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step-by-step explanation: