Each side of the smaller square in the figure below is n inches long, and each side of the larger square is p inches longer than a side of the smaller square. the area of the larger square is how many square inches greater than the area of the smaller square?

2np + p²

Step-by-step explanation:

The general formula for the area of a square is A = s², where s = the length of one side of the square.  In the case of the smaller square the area would be: n x n = n².  Since the side of the larger square is 'p' inches longer, the length of one side is 'n + p'.  To find the area of the larger square, we have to take the length x length or (n +p)².

Using FOIL (forward, outside, inside, last):

(n + p)(n+p) = n² + 2np + p²

Since the area of the first triangle is n², we can subtract this amount from the area of the larger square to find out how many square inches greater the larger square area is.

n² + 2np + p² - n² = 2np + p²

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!

cheater

step-by-step explanation: