Find the length of the diagonal of a square with perimeter of 24

d = 6sqrt(2) or 8.4853

Step-by-step explanation:

Formula

P = 4*s

s^2 + s^2 = d^2 where d is the diagonal and s is the side.

Givens

P = 24

Solution

P = 4s         Substitute for s

24 = 4*s      Divide by 4

24/4 = s

s = 6

d^2 = s^2 + s^2

d^2 = 6^2 + 6^2

d^2 = 36 + 26

d^2 = 72

d = sqrt(72)

Factors of 72

72: 6 * 6 * 2

Rule: Every pair of = factors allows you to take one of them outside the sqrt sign and throw the other a way. If there are no pairs, whatever you started with stays under the root sign.

sqrt(6*6*2) = 6sqrt(2)

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!

you could deduce the conclusion directly using the facts pertaining to the specific situation.

hope this .