Me add. 4x^2-5x+3 + 2x^2+7x-8 a. 6x^2+2x-5 b. 6x^2+2x+11 c. 6x^2-2x+5 d. 6x^2+12x-5

a

Step-by-step explanation:

To sum the 2 expressions collect like terms

4x² - 5x + 3 + 2x² + 7x - 8

= (4x² + 2x² ) + (- 5x + 7x ) + (3 - 8 )

= 6x² + 2x + (- 5)

=6x² + 2x - 5 → a

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.