What are the real zeros in f(x)=x^3+8

-2

Step-by-step explanation:

f(x)=x^3+8

Set it equal to 0

0 = x^2 +8

Subtract 8 from each side

-8 = x^3+8-8

-8 = x^3

Take the cube root of each side

-8 ^ 1/3 = x^3 ^ 1/3

-2 = x

The only real root is -2

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !