Abookmark is shaped like a rectangle with a semicircle attached at both ends. the rectangle is 14 cm long and 4 cm wide. the diameter of each circle is the width of the rectangle. what is the area of the bookmark? use 3.14 for π. pls due tommorrow.

Area of the bookmar = 68.56 sq.cm.

Step-by-step explanation:

It is given that the diameter of each circle is the width of the rectangle.

Therefore, each radius = = 2 cm.

Area of the 2 semi circles = 2 × 0.5 × 3.14 ×

= 4 × 3.14

= 12.56 sq.cm.

Now, area of the rectangle = length × width

= 14 × 4

= 56 sq.cm

Area of the bookmark = Area of the rectangular part + 2 × (area of the semicircular part)

= 56 + 12.56

= 68.56 sq.cm.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3