How to systematically enumerate all possibilities of +b)+c)+d)+e? i know that when (a+b)+c=a+(b+c) then to do ((a+b)+c)+d =(a+b)+(c+d) < --"counted" all possible outer brackets =(a+(b+c))+d < -- just "slide" the brackets off =a+((b+c)+d) a+(b+(c+d)) < -- by finish '"sliding" i should get the originals questions mirror image as a result.

answer: no

step-by-step explanation: because the big angle will spread away the 2 side that it is on and make the opposite side even longer.

whaere is the picture

step-by-step explanation:

ιт ιѕ $222.95

step-by-step explanation:

αℓℓ уσυ gσт тσ ∂σ ιѕ fιgυяє συт ωнαт 30% σf $318.50 ιѕ $95.55

тнєи ѕυвтяα¢т ιт fяσм $318.50-$95.55=$222.95

нσρє ι ¢συℓ∂ нєℓρ уσυ συ