Ametalworker has a metal alloy that is 20% copper and another alloy that is 65% copper. how many kilograms of each alloy should the metalworker combine to create 100 kg of a 56% copper alloy? the metalworker should use _kilograms of the metal alloy that is 20% copper and _kilograms of the metal alloy that is 65% copper. (type whole numbers.)

The metallurgist must use 20 kilograms of the metal alloy which is 20% copper and 80 kilograms of the metal alloy which is 65% copper.

Step-by-step explanation:

We call the alloy 20% copper.

We call the alloy 65% copper.

Let's call the new version you want to create.

When mixing the M Alloy with the S you want to obtain 100 kg of the new alloy

   (i)

Then

   (ii)

We substitute (i) in (ii)

   (iii)

Now we substitute (iii) in (i)

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.

step-by-step explanation:

the triangles are similar. therefore the corresponding sides are in proportion:

              cross multiply

            divide both sides by 32