*plz answer fast *in the figure, a∥b and m∠3 = 34°. what is the m∠7 ? enter your answer in the box. ° severely slanted line c diagonally crossing parallel lines a and b (reading from top to bottom). angles formed by c crossing a are labeled one through four, starting at top right and going counterclockwise, where angle one is acute. angles formed by c crossing b are labeled five through eight, starting at top right and going counterclockwise.

m∠7 = 34°

Step-by-step explanation:

For better understanding of the solution see the attached figure :

From the question, line a is parallel to line b and line c is transversal to both the parallel lines a and b

Next, we name the angles as given in the question and obtain the resulting named figure of the problem.

Now, m∠3 = 34°

Since, a ║ b

⇒ m∠3 + m∠6 = 180° (Sum of co-interior opposite angles is 180°)

⇒ m∠6 = 180° - m∠3

⇒ m∠6 = 180° - 34°

⇒ m∠6 = 126°

Now, m∠6 + m∠7 = 180° (Sum of linear pair is 180°)

⇒ m∠7 = 180° - m∠6

⇒ m∠7 = 180° - 126°

⇒ m∠7 = 34°

m∠7 = 34°

Step-by-step explanation:

For better understanding of the solution see the attached figure :

From the question, line a is parallel to line b and line c is transversal to both the parallel lines a and b

Next, we name the angles as given in the question and obtain the resulting named figure of the problem.

Now, m∠3 = 34°

Since, a ║ b

⇒ m∠3 + m∠6 = 180° (Sum of co-interior opposite angles is 180°)

⇒ m∠6 = 180° - m∠3

⇒ m∠6 = 180° - 34°

⇒ m∠6 = 126°

Now, m∠6 + m∠7 = 180° (Sum of linear pair is 180°)

⇒ m∠7 = 180° - m∠6

⇒ m∠7 = 180° - 126°

⇒ m∠7 = 34°

Step-by-step explanation:

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