Two hikers start from the same point and hike in opposite directions around a lake whose shoreline is 15 mi long. one hiker walks 0.5 mph faster than the other hiker. how fast did each hiker walk if they meet in 2 h?

Step-by-step explanation:

Let the distance the slower hiker travels=d,

the distance the faster hiker travels=15-d (Since, the sum of the distances they walk is 15mi).

Let the speed of the slower hiker in mi/hr=s,

the speed of the faster hiker=s+0.5

Now, equation for the slow hiker:

                                                           (1)

and equation for the faster hiker:

                                                      (2)

Now, substituting the equation (1) in equation (2),

and

The speed of the slower hiker is and The speed of the faster hiker is .

step-by-step explanation:

cats

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4