#63.)in the window bd ~= df~=hf. also need aswell with part a and b to the problem. attached a picture file below for a better understanding. a.) b.)

A) HBDF is a rhombus; ACEG is a rectangle

B) The diagonals are congruent; the listed half-diagonals are congruent

Step-by-step explanation:

A) A quadrilateral (HBDF) with equal length sides (given) is a rhombus (by definition).

A quadrilateral (ACEG) with right-angle corners is a rectangle (by definition).

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B) The diagonals AE and GC are those of a rectangle, so are congruent and bisect each other. Hence, the pieces are all congruent.

35 is an outlier

step-by-step explanation:

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: