For the functions f(x) =x^2-9 and g(x) =2x+3 a) find the function (g/f) (x) b) find the domain of (g/f) (x)

              2x + 3

(g/f)(x) =

               x^2 - 9

all real numbers other than +3 and -3

Step-by-step explanation:

If:  f(x) =x^2-9 and g(x) =2x+3,

then the quotient function (g/f)(x) is as follows:

              2x + 3

(g/f)(x) =

               x^2 - 9

The denominator here determines the domain:  Because we cannot divide by zero, we intentionally set the denominator x^2 - 9 = to zero and solve for x:  The solutions are +3 and -3.  

The domain consists of "all real numbers other than +3 and -3," or:

(-infinity, -3) ∪ (-3, 3), ∪ (3, infinity)

2? if not the correct answer you might need to provide more information

step-by-step explanation:

n

step-by-step explanation: